Bài 3:
\(\Leftrightarrow x^3-6x^2+12x-8-3\left(4x^2-4x+1\right)=x^3+9x^2+27x+27-2\left(9x^2+6x+1\right)-x^2+5x-6\)
\(\Leftrightarrow-6x^2+12x-8-12x^2+12x-3=9x^2+27x+27-18x^2-12x-2-x^2+5x-6\)
\(\Rightarrow-18x^2+24x-11=-10x^2+20x+19\)
\(\Leftrightarrow-8x^2+4x-30=0\)
\(\Leftrightarrow4x^2-2x+15=0\)
\(\text{Δ}=\left(-2\right)^2-4\cdot4\cdot15=4-240=-236< 0\)
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