Violympic toán 9
Các câu hỏi tương tự
GPT : \(\sqrt{x^2-3x+2}+\sqrt{x+3}=\sqrt{x-2}+\sqrt{x^2+2x-3}\)
gpt : a. \(x^2-7x=6\sqrt{x+5}-30\)
b. \(\sqrt{3x^2-5x+1}-\sqrt{x^2-2}=\sqrt{3\left(x^2-x-1\right)}-\sqrt{x^2-3x-4}\)
gpt:
\(\sqrt{x^3+x^2+3x+3}+\sqrt{2x}=\sqrt{x^2+3}+\sqrt{2x^2+2x}\)
1 tháng 7 2019 lúc 22:07
Gpt : a) \(\sqrt{x-1}+\sqrt{x+3}+2\sqrt{\left(x-1\right)\left(x^2-3x+5\right)}=4-2x\)
b) \(\sqrt[4]{1-x}+\sqrt[4]{2-x}=\sqrt[4]{3-2x}\)
c) \(\sqrt{x+1}+\sqrt{x+10}=\sqrt{x+2}+\sqrt{x+5}\)
GPT
\(x^2-3\sqrt[3]{3x-2}-12+\frac{1}{\sqrt{x}}=\frac{\sqrt{x}+8}{x}\)
GPT : x = \(\sqrt{2-x}\cdot\sqrt{3-x}+\sqrt{3-x}\cdot\sqrt{5-x}+\sqrt{5-x}\cdot\sqrt{2-x}\)
GPT
2x3-x2-3x+1=\(\sqrt{x^5+x^4+1}\)
`GPT:
\(\sqrt[3]{x+3}+\sqrt[3]{5-x}=2\)
1 tháng 1 2020 lúc 22:36
gpt : a) \(\frac{5x}{\sqrt{4-x^2}}+\frac{8}{x^2}+\frac{2x}{4-x^2}+\frac{5\sqrt{4-x^2}}{x}+4=0\)
b) \(\frac{2x}{\sqrt{8x^2+25}}+\frac{125}{x^2}-14=0\)
c) \(\left(x^3-3x+2\right)\sqrt{3x-2}-2x^3+6x^2-4x=0\)
d) \(\sqrt{x^2-x+6}+\frac{4}{x-1}=x^2+x\)