\(\widehat{HAC}=\widehat{BCA}=30^0\left(sole\right)\)
Bz// Ay > \(\widehat{H}=\widehat{B}=90^0\)
\(\Delta\)HAI cho ta HI/AI = 1/2 và \(\Delta\)BCI cho ta BỊ/CI =1/2 (là nửa tam giác đều)
\(\dfrac{HI}{AI}=\dfrac{BI}{CI}=\dfrac{HI+BI}{AI+CI}=\dfrac{BH}{AC}=\dfrac{1}{2}\)
vay \(\dfrac{BH}{AC}=\dfrac{1}{2}\)
