Question

Giúp tớ với cảm ơn nhiều ạ

Answer 1

a: \(\Leftrightarrow x^2-2x+1=0\)

\(\Leftrightarrow\left(x-1\right)^2=0\)

=>x=1

b: \(\Leftrightarrow x^2+6x+9=0\)

\(\Leftrightarrow\left(x+3\right)^2=0\)

=>x=-3

c: \(\Leftrightarrow4x^2-6x+2x+1=0\)

\(\Leftrightarrow4x^2-4x+1=0\)

\(\Leftrightarrow\left(2x-1\right)^2=0\)

hay x=1/2

Answer 2

a, `=> x^2 - 2x + 1 = 0`

`=> (x-1)^2 = 0`

`=> x = 1`

`b, => (x+3)^2 = 0`

`=> x + 3 = 0`

`=> x = -3`.

`c, 4x^2 - 6x = -2x -1`

`=> 4x^2 -4x+1 = 0`

`=> (2x-1)^2 = 0`

`=> x = 1/2`.

`d, x^2 - 3x = 2x - 6`

`=> x^2 -5x + 6 = 0`

`=> (x-2)(x-3)=0`

`=> x = 2` hoặc `x = 3`.

Answer 3

a) \(x\left(x-2\right)=-1\\ \Leftrightarrow x^2-2x=-1\\ \Leftrightarrow x^2-2x+1=0\\ \Leftrightarrow\left(x-1\right)^2=0\\ \Leftrightarrow x=1\)

b) \(x\left(x+6\right)=-9\\ \Leftrightarrow x^2+6x=-9\\ \Leftrightarrow x^2+6x+9=0\\ \Leftrightarrow\left(x+3\right)^2=0\\ \Leftrightarrow x=-3\)

c) \(2x\left(2x-3\right)=-2x-1\\ \Leftrightarrow4x^2-6x+2x+1=0\\ \Leftrightarrow4x^2-4x+1=0\\ \Leftrightarrow\left(2x-1\right)^2=0\\ \Leftrightarrow x=\dfrac{1}{2}\)

d) \(x\left(x-3\right)=2x-6\\ \Leftrightarrow x\left(x-3\right)-2x+6=0\\ \Leftrightarrow x\left(x-3\right)-2\left(x-3\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\)