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Answer 1

b: \(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{50}{x-1}+\dfrac{5}{y+2}=5\\\dfrac{50}{x-1}+\dfrac{6}{y+2}=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y+2=-1\\\dfrac{10}{x-1}=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=6\\y=-3\end{matrix}\right.\)