Question

giải pt

|x-3|+|x-4|=11

Answer 1

\(\Leftrightarrow\left[{}\begin{matrix}3-x+4-x=11\left(x< 3\right)\\x-3+4-x=11\left(3\le x< 4\right)\\x-3+x-4=11\left(x\ge4\right)\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\left(tm\right)\\0x+1=11\left(ktm\right)\\x=9\left(tm\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=9\end{matrix}\right.\)