\(2sinx+\sqrt{3}cos2x+1-cos\left(2x-\frac{\pi}{2}\right)=1\)
\(\Leftrightarrow2sinx+\sqrt{3}cos2x-sin2x=0\)
\(\Leftrightarrow\frac{1}{2}sin2x-\frac{\sqrt{3}}{2}cos2x=sinx\)
\(\Leftrightarrow sin\left(2x-\frac{\pi}{3}\right)=sinx\)
\(\Leftrightarrow...\)