(x + 1)3 - (x - 2)3 = (3x - 1)(3x + 1)
\(\Leftrightarrow\) (x + 1 - x + 2)[(x + 1)2 + (x + 1)(x - 2) + (x - 2)2] = (3x - 1)(3x + 1)
\(\Leftrightarrow\) 3(x2 + 2x + 1 + x2 - 2x + x - 2 + x2 - 4x + 4) = 9x2 - 1
\(\Leftrightarrow\) 3(3x2 - 3x + 3) = 9x2 - 1
\(\Leftrightarrow\) 9x2 - 9x + 9 = 9x2 - 1
\(\Leftrightarrow\) 9x2 - 9x2 - 9x = -1 - 9
\(\Leftrightarrow\) -9x = -10
\(\Leftrightarrow\) x = \(\frac{10}{9}\)
Vậy S = {\(\frac{10}{9}\)}
Chúc bn học tốt!!