Question

giải phương trình 

\(\dfrac{1}{x-1}+\dfrac{1}{x-1}=\dfrac{4}{3}\)

Answer 1

\(\dfrac{1}{x-1}+\dfrac{1}{x-1}=\dfrac{4}{3}\)

\(\dfrac{2}{x-1}=\dfrac{4}{3}\)

\(4x-4=6\)

\(4x=10\)

\(x=\dfrac{5}{2}\)

Answer 2

2/x-1=4/3

4x-4=6

4x=10

x=5/2

Answer 3

\(=>\dfrac{2}{x-1}=\dfrac{4}{3}\)

\(=>4\left(x-1\right)=2.3\)

\(=>4x-4=6\)

\(=>4x=10\)

\(=>x=\dfrac{10}{4}=\dfrac{5}{2}\)

Answer 4

\(\dfrac{1}{x-1}+\dfrac{1}{x-1}=\dfrac{4}{3}\)

\(⇔\dfrac{2}{x-1}=\dfrac{4}{3}\)

\(⇔4(x-1)=6\)

\(⇔4x=10\)

\(⇔x=\dfrac{5}{2}\)

Answer 5

5/2

Answer 6

quy đồng r khử mẫu là ok