\(\left|5x-4\right|=\left|x+1\right|\)
\(\Leftrightarrow5x-4=x+1\) hoặc \(5x-4=-x-1\)
\(\Leftrightarrow5x-x=1+4\) hoặc \(5x+x=-1+4\)
\(\Leftrightarrow4x=5\) hoặc \(6x=3\)
\(\Leftrightarrow x=\dfrac{5}{4}\) (TMĐK) hoặc \(x=\dfrac{1}{2}\)(TMĐK)
Vậy phương trình có tập nghiệm S = \(\left\{\dfrac{5}{4};\dfrac{1}{2}\right\}\)
Ta có: \(\left|5x-4\right|=\left|x+1\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}5x-4=x+1\\5x-4=-x-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=5\\6x=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{2}\end{matrix}\right.\)
Vậy: \(S=\left\{\dfrac{5}{4};\dfrac{1}{2}\right\}\)
