\(2sin^2x+cosx=0\Rightarrow2\left(1-cos^2x\right)+cosx=0\)
\(\Rightarrow-2cos^2x+cosx+2=0\)
\(\Rightarrow\left[{}\begin{matrix}cosx=\dfrac{1+\sqrt{17}}{4}\left(loại\right)\\cosx=\dfrac{1-\sqrt{17}}{4}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=arccos\dfrac{1-\sqrt{17}}{4}+k2\pi\\x=-arccos\dfrac{1-\sqrt{17}}{4}+k2\pi\end{matrix}\right.\)