Phương trình bậc nhất một ẩn
Các câu hỏi tương tự
Bài tập: Giải các phương trình sau:
1. \(\dfrac{5-x}{2003}-2=\dfrac{2-x}{2004}-\dfrac{5x}{2003}\)
2. \(\dfrac{3x+1}{2002}+1=\dfrac{2-3x}{2003}+\dfrac{4x+2}{2001}\)
Giải Phương trình :
\(a,\frac{1-x}{2013}=1+\frac{2-x}{2012}-\frac{x}{2014}\)
\(b,\frac{2-x}{2001}-1=\frac{1-x}{2002}-\frac{x}{2003}\)
\(c,\frac{x-a-b}{c}+\frac{x-b-c}{a}+\frac{x-a-c}{b}=3\)
a . \(\dfrac{2-x}{2001}-1=\dfrac{1-x}{2002}-\dfrac{x}{2003}\)
b . \(\dfrac{x-5}{100}+\dfrac{x-4}{101}=\dfrac{x-100}{5}+\dfrac{x-101}{4}\)
Mik cần gấp lắm . Thanks
Giải các phương trình sau
a) frac{x-23}{24}+frac{x-23}{25}frac{x-23}{26}+frac{x-23}{27}
b) left(frac{x+2}{98}+1right)+left(frac{x+3}{97}+1right)left(frac{x+4}{96}+1right)+left(frac{x+5}{95}+1right)
c) frac{x+1}{2004}+frac{x+2}{2003}frac{x+3}{2002}+frac{x+4}{2001}
d) frac{201-x}{99}+frac{203-x}{97}frac{205-x}{95}+30
Đọc tiếp
Giải các phương trình sau
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
b) \(\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)=\left(\frac{x+4}{96}+1\right)+\left(\frac{x+5}{95}+1\right)\)
c) \(\frac{x+1}{2004}+\frac{x+2}{2003}=\frac{x+3}{2002}+\frac{x+4}{2001}\)
d) \(\frac{201-x}{99}+\frac{203-x}{97}=\frac{205-x}{95}+3=0\)
Baif 1 : giải phương trình
a. dfrac{x-23}{24}+dfrac{x-23}{25}dfrac{x-23}{26}+dfrac{x-23}{27}
b. left(dfrac{x+2}{98}+1right)+left(dfrac{x+3}{97}+1right)left(dfrac{x+4}{96}+1right)left(dfrac{x+5}{95}+1right)
c. dfrac{x+1}{2004}+dfrac{x+2}{2003}dfrac{x+3}{2002}+dfrac{x+4}{2001}
d. dfrac{201-x}{99}+dfrac{203-x}{97}+dfrac{205-x}{95}+30
e.dfrac{x-45}{55}+dfrac{x-47}{53}dfrac{x-55}{45}+dfrac{x-53}{47}
f. dfrac{x+1}{9}+dfrac{x+2}{8}dfrac{x+3}{7}+dfrac{x+4}{6}
h. dfrac{2-x}{2002}-1dfrac{1-x}{2003}...
Đọc tiếp
Baif 1 : giải phương trình
a. \(\dfrac{x-23}{24}+\dfrac{x-23}{25}=\dfrac{x-23}{26}+\dfrac{x-23}{27}\)
b. \(\left(\dfrac{x+2}{98}+1\right)+\left(\dfrac{x+3}{97}+1\right)=\left(\dfrac{x+4}{96}+1\right)\left(\dfrac{x+5}{95}+1\right)\)
c. \(\dfrac{x+1}{2004}+\dfrac{x+2}{2003}=\dfrac{x+3}{2002}+\dfrac{x+4}{2001}\)
d. \(\dfrac{201-x}{99}+\dfrac{203-x}{97}+\dfrac{205-x}{95}+3=0\)
e.\(\dfrac{x-45}{55}+\dfrac{x-47}{53}=\dfrac{x-55}{45}+\dfrac{x-53}{47}\)
f. \(\dfrac{x+1}{9}+\dfrac{x+2}{8}=\dfrac{x+3}{7}+\dfrac{x+4}{6}\)
h. \(\dfrac{2-x}{2002}-1=\dfrac{1-x}{2003}-\dfrac{x}{2004}\)
g. \(\dfrac{x+2}{98}+\dfrac{x+4}{96}=\dfrac{x+6}{94}+\dfrac{x+8}{92}\)
I : Giải các phương trình sau :
a) dfrac{x+1}{2004}+dfrac{x+2}{2003}dfrac{x+3}{2002}+dfrac{x+4}{2001}
b) dfrac{x-45}{55}+dfrac{x-47}{53}dfrac{x-55}{45}+dfrac{x-53}{47}
c) dfrac{x+2}{98}+dfrac{x+4}{96}dfrac{x+6}{94}+dfrac{x+8}{92}
d) dfrac{201-x}{99}+dfrac{203-x}{97}+dfrac{205-x}{95}+30
e) dfrac{x+1}{9}+dfrac{x+2}{8}dfrac{x+3}{7}+dfrac{x+4}{6}
f) dfrac{2-x}{2002}-1dfrac{1-x}{2003}-dfrac{x}{2004}
g) dfrac{x^2-10x-29}{1971}+dfrac{x^2-10x-27}{1973}dfrac{x^2-10x-1971}{29}+dfrac{x^2-10x-197...
Đọc tiếp
I : Giải các phương trình sau :
a) \(\dfrac{x+1}{2004}+\dfrac{x+2}{2003}=\dfrac{x+3}{2002}+\dfrac{x+4}{2001}\)
b) \(\dfrac{x-45}{55}+\dfrac{x-47}{53}=\dfrac{x-55}{45}+\dfrac{x-53}{47}\)
c) \(\dfrac{x+2}{98}+\dfrac{x+4}{96}=\dfrac{x+6}{94}+\dfrac{x+8}{92}\)
d) \(\dfrac{201-x}{99}+\dfrac{203-x}{97}+\dfrac{205-x}{95}+3=0\)
e) \(\dfrac{x+1}{9}+\dfrac{x+2}{8}=\dfrac{x+3}{7}+\dfrac{x+4}{6}\)
f) \(\dfrac{2-x}{2002}-1=\dfrac{1-x}{2003}-\dfrac{x}{2004}\)
g) \(\dfrac{x^2-10x-29}{1971}+\dfrac{x^2-10x-27}{1973}=\dfrac{x^2-10x-1971}{29}+\dfrac{x^2-10x-1973}{27}\)
các bạn ơi giúp mình với
mình cảm ơn
Giải các phương trình sau:
a) \(\frac{x-15}{2000}+\frac{x-14}{2001}+\frac{x-13}{2003}=\frac{x-12}{2003}+2\)
b) \(\left(x^2-6x+11\right)\left(y^2+2y+4\right)=2+4z-z^2\)
Giải phương trình sau:
a)\(\frac{201-x}{99}+\frac{203-x}{97}=\frac{205-x}{95}+3=0\)
b)\(\frac{2-x}{2002}-1=\frac{1-x}{2003}-\frac{x}{2004}\)
c)\(\frac{x^2-10x-29}{1971}+\frac{x^2-10x-27}{1973}=\frac{x^2-10x-1971}{29}+\frac{x^2-10x-1973}{27}\)
5 tháng 3 2021 lúc 21:27
Giải phương trình :a,\(\dfrac{2x 1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)b,\(\dfrac{3\left(2x 1\right)}{4}-5-\dfrac{3x 2}{10}=\dfrac{2\left(3x-1\right)}{5}\)\(c,\dfrac{x 1}{2009} \dfrac{x 3}{2007}=\dfrac{x 5}{2005} \dfrac{x 7}{2003}\)\(d,\dfrac{392-x...
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