\(\Leftrightarrow4m^2+4n^2=4m+4m+32\)
\(\Leftrightarrow\left(2m-1\right)^2+\left(2n-1\right)^2=34=3^2+5^2\)
\(\Rightarrow\left\{{}\begin{matrix}\left(2m-1\right)^2=3\\\left(2n-1\right)^2=5\end{matrix}\right.\) hoặc \(\left\{{}\begin{matrix}\left(2m-1\right)^2=5\\\left(2n-1\right)^2=3\end{matrix}\right.\)
Giải ta m;n dễ dàng, bạn tự giải nốt nhé