Question

Giải chi tiết giúp e vs

Answer 1

\(y'=-2\left(x+2\right)^{-3}\)

\(y''=6\left(x+2\right)^{-4}=6\left[\left(x+2\right)^{-2}\right]^2=6y^2\)

\(\Rightarrow y''-6y^2=0\)