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§5. Dấu của tam thức bậc hai
Các câu hỏi tương tự
Bài 3 : Xét dấu biểu thức sau :
1 , fleft(xright)frac{x-7}{4x^2-19x+12}
2 , fleft(xright)frac{11x+3}{-x^2+5x-7}
3 , fleft(xright)frac{3x-2}{x^3-3x^2+2}
4 , fleft(xright)frac{x^2+4x-12}{sqrt{6}x^2+3x+sqrt{2}}
5 , fleft(xright)frac{x^2-3x-2}{-x^2+x-1}
6 , fleft(xright)frac{x^3-5x+4}{x^4-4x^3+8x-5}
7 , fleft(xright)frac{left(x+3right)left(x-2right)left(-2x^2+x-1right)}{left(2x-5right)left(x^2+3x-10right)}
8 , fleft(xright)left(-x^2+x-1right)left(6x^2-5x+1right)
9 , fleft(xright)frac{x^2-...
Đọc tiếp
Bài 3 : Xét dấu biểu thức sau :
1 , \(f\left(x\right)=\frac{x-7}{4x^2-19x+12}\)
2 , \(f\left(x\right)=\frac{11x+3}{-x^2+5x-7}\)
3 , \(f\left(x\right)=\frac{3x-2}{x^3-3x^2+2}\)
4 , \(f\left(x\right)=\frac{x^2+4x-12}{\sqrt{6}x^2+3x+\sqrt{2}}\)
5 , \(f\left(x\right)=\frac{x^2-3x-2}{-x^2+x-1}\)
6 , \(f\left(x\right)=\frac{x^3-5x+4}{x^4-4x^3+8x-5}\)
7 , \(f\left(x\right)=\frac{\left(x+3\right)\left(x-2\right)\left(-2x^2+x-1\right)}{\left(2x-5\right)\left(x^2+3x-10\right)}\)
8 , \(f\left(x\right)=\left(-x^2+x-1\right)\left(6x^2-5x+1\right)\)
9 , \(f\left(x\right)=\frac{x^2-x-2}{-x^2+3x+4}\)
10 , \(f\left(x\right)=\left(x^2-5x+4\right)\left(2-5x+2x^2\right)\)
Bài 2 Xét dấu biểu thức sau
1 , fleft(xright)x^2-sqrt{3}x+frac{3}{4}
2 , fleft(xright)-x^2+3x-2
3 , fleft(xright)x^4-4x+1
4 , fleft(xright)frac{3x+7}{x^2-x-2}
5 , fleft(xright)frac{x+2}{3x+1}-frac{x-2}{2x-1}
6 , fleft(xright)frac{1}{x^2-5x+4}-frac{1}{x^2-7x+10}
7 , fleft(xright)left(x-1right)left(x-3right)-frac{18}{x^2-4x-4}
8 , fleft(xright)left(x^2-1right)left(x-2right)
9 , fleft(xright)left(x+3right)left(-4x^2+9x-2right)
10 , fleft(xright)frac{10-x}{5+x^2}-frac{1}{2}
Đọc tiếp
Bài 2 Xét dấu biểu thức sau
1 , \(f\left(x\right)=x^2-\sqrt{3}x+\frac{3}{4}\)
2 , \(f\left(x\right)=-x^2+3x-2\)
3 , \(f\left(x\right)=x^4-4x+1\)
4 , \(f\left(x\right)=\frac{3x+7}{x^2-x-2}\)
5 , \(f\left(x\right)=\frac{x+2}{3x+1}-\frac{x-2}{2x-1}\)
6 , \(f\left(x\right)=\frac{1}{x^2-5x+4}-\frac{1}{x^2-7x+10}\)
7 , \(f\left(x\right)=\left(x-1\right)\left(x-3\right)-\frac{18}{x^2-4x-4}\)
8 , \(f\left(x\right)=\left(x^2-1\right)\left(x-2\right)\)
9 , \(f\left(x\right)=\left(x+3\right)\left(-4x^2+9x-2\right)\)
10 , \(f\left(x\right)=\frac{10-x}{5+x^2}-\frac{1}{2}\)
Giải bpt
\(\frac{\left|x^2-4x\right|+3}{x^2+\left|x-5\right|}\ge1\)
Tìm m để bpt \(\left(x-m\right)\left(x^2+x-2\right)\ge0\) nghiệm đúng với mọi x dương
1) frac{x^2+2x+5}{x+4}ge x-3
2) frac{x^2-3x-1}{2-x}-x
3) frac{3x-47}{3x-1}frac{4x-47}{2x-1}
4) x+frac{9}{x+2}ge4
5) frac{left(x-1right)^3left(x+2right)^4left(x+6right)}{left(x-7right)^3left(x-2right)^2}le0
6) x^4geleft(x^2+4x+2right)^27x^2-7x+10 0
Đọc tiếp
1) \(\frac{x^2+2x+5}{x+4}\ge x-3\)
2) \(\frac{x^2-3x-1}{2-x}>-x\)
3) \(\frac{3x-47}{3x-1}>\frac{4x-47}{2x-1}\)
4) \(x+\frac{9}{x+2}\ge4\)
5) \(\frac{\left(x-1\right)^3\left(x+2\right)^4\left(x+6\right)}{\left(x-7\right)^3\left(x-2\right)^2}\le0\)
6) \(x^4\ge\left(x^2+4x+2\right)^27x^2-7x+10< 0\)
Giải các bpt sau
a, \(\frac{\left(4-x\right)\left(x^2-2x-15\right)}{2x^2+x+1}\le0\)
b, \(\frac{x^2+x-3}{x^2-4}\ge1\)
1. Giải các phương trình sau :
a, \(\frac{x^2-4x+4}{x^2-2x+1}+\frac{\left|2x-4\right|}{\left|x-1\right|}-3=0\)
b, \(\left|x^2-5\right|x\left|+4\right|=\left|2x^2-3\right|x\left|+1\right|\)
Bài 4 Xét dấu biểu thức sau
1 , fleft(xright)x^2-3x-2-frac{8}{x^2-3x}
2 , fleft(xright)frac{1}{x+1}-frac{1}{x}-frac{1}{2}
3 , fleft(xright)frac{x^2-4x+3}{3-2x}-1+x
4 , fleft(xright)frac{x^2-1}{left(x^2-3right)left(-3x^2+2x+8right)}
5 , fleft(xright)x^4-5x^2+2x+3
6 , fleft(xright)frac{x^2+4x+15}{x^2-1}-frac{x-3}{x+1}-frac{x-2}{1-x}
Đọc tiếp
Bài 4 Xét dấu biểu thức sau
1 , \(f\left(x\right)=x^2-3x-2-\frac{8}{x^2-3x}\)
2 , \(f\left(x\right)=\frac{1}{x+1}-\frac{1}{x}-\frac{1}{2}\)
3 , \(f\left(x\right)=\frac{x^2-4x+3}{3-2x}-1+x\)
4 , \(f\left(x\right)=\frac{x^2-1}{\left(x^2-3\right)\left(-3x^2+2x+8\right)}\)
5 , \(f\left(x\right)=x^4-5x^2+2x+3\)
6 , \(f\left(x\right)=\frac{x^2+4x+15}{x^2-1}-\frac{x-3}{x+1}-\frac{x-2}{1-x}\)
Giải hệt bất phương trình sau:
\(\left\{{}\begin{matrix}\left(x+5\right)\left(x-2\right)+3\sqrt{x\left(x+3\right)}>0\\x+5\ge0\end{matrix}\right.\)