ĐKXĐ: x\(\ne-2\)
Ta có: \(\dfrac{144}{x+2}-\dfrac{100}{x}=2\)
<=> \(\dfrac{144x}{\left(x+2\right)x}-\dfrac{100\left(x+2\right)}{\left(x+2\right)x}=\dfrac{2\left(x+2\right)x}{\left(x+2\right)x}\)
=> 144x-100(x+2)=2(x+2)x
<=> 144x-100x-200=2x2+4x
<=> 44x-4x-2x2-200=0
<=> 40x-2x2-200=0
<=> 2(20x-x2-100)=0
=> 20x-x2-100=0
<=> -(x-10)2=0
=> (x-10)2=0
<=> x-10=0
<=> x=10 (thỏa mãn ĐKXĐ)
Vậy S=\(\left\{10\right\}\)