Question

\(\frac{3\left(3-x\right)}{8}+\frac{2\left(5-x\right)}{3}=\frac{1-x}{2}-2\)

Answer 1

Ta có: \(\frac{3\left(3-x\right)}{8}+\frac{2\left(5-x\right)}{3}=\frac{1-x}{2}-2\)

\(\Leftrightarrow\frac{9\left(3-x\right)}{24}+\frac{16\left(5-x\right)}{24}=\frac{12\left(1-x\right)}{24}-\frac{48}{24}\)

\(\Leftrightarrow27-9x+80-16x=12-12x-48\)

\(\Leftrightarrow107-25x=-12x-36\)

\(\Leftrightarrow107-25x+12x+36=0\)

\(\Leftrightarrow-13x+143=0\)

\(\Leftrightarrow-13x=-143\)

hay x=11

Vậy: S={11}