\(\frac{1}{3}x+\frac{2}{5}\left(x+1\right)=0\)
⇔\(\frac{x}{3}+\frac{2x}{5}+\frac{2}{5}=0\)
⇔\(\frac{5x}{15}+\frac{6x}{15}+\frac{6}{5}=0\)
⇔\(\frac{11x+6}{15}=0\)
⇔11x+6=0
⇔x=\(\frac{-6}{11}\)
\(\frac{1}{3}x+\frac{2}{5}\left(x+1\right)=0\)
⇔\(\frac{x}{3}+\frac{2x}{5}+\frac{2}{5}=0\)
⇔\(\frac{5x}{15}+\frac{6x}{15}+\frac{6}{5}=0\)
⇔\(\frac{11x+6}{15}=0\)
⇔11x+6=0
⇔x=\(\frac{-6}{11}\)
1) Tìm x:
a) \(\frac{11}{12}-\frac{5}{12}.\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
b) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
c) 2x.(x-\(\frac{1}{7}\))=0
d) (x + 1) . (x - 2) < 0
e) (x - 2) . ( x + \(\frac{2}{3}\) ) >0
1. x : (\(\frac{2}{9}-\frac{1}{5}\))=\(\frac{8}{16}\)
2. a)\(\frac{x-3}{-2}\)>0
b) \(x^2\)+x >0
c) \(\frac{x+3}{x-5}\)<0
bài 1:
a, (-\(2\frac{1}{5}\)).(\(\frac{-9}{11}\)).(-1\(\frac{1}{14}\)).\(\frac{2}{5}\)
b, [\(\frac{5}{3}\)- (-\(\frac{1}{4}\)): 1\(\frac{1}{5}\)]: (\(\frac{5}{8}\)+\(\frac{9}{4}\))
c,-66. (\(\frac{1}{2}\)- \(\frac{1}{3}\)+ \(\frac{1}{11}\))+124. -37+ 63. (-123)
d, C= \(\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}-\frac{2}{7}-\frac{2}{13}}\). \(\frac{\frac{1}{3}-0,25+0,2}{1\frac{1}{6}-0,875+0,7}\)+ \(\frac{6}{7}\)
e, D= (\(\frac{1}{4}\)-1). (\(\frac{1}{9}\)-1).(\(\frac{1}{16}\)-1)....(\(\frac{1}{81}\)-1).(\(\frac{1}{100}\)-1)
bài 2:
a, x: (\(\frac{2}{9}\)-\(\frac{1}{5}\))=\(\frac{8}{16}\)
b,(2x-1).(2x+3)=0
c,\(\frac{4-3x}{2x+5}\)=0
d,(x-2). (x+\(\frac{2}{3}\))≥0
e, \(\frac{x-2}{3x+2}\)<0
MỌI NGƯỜI LÀM NHANH GIÚP MÌNH VỚI. MÌNH ĐANG CẦN GẤP TRONG 3H CHIỀU NAY
a) x = \(\frac{-1}{7}\) b) x = \(\frac{1}{7}\) c) x = -3\(\frac{1}{5}\) d) x = 0
Tìm tập hợp các số nguyên x , biết : 4\(\frac{5}{9}\) : 2\(\frac{5}{18}\) - 7 < x < 3\(\frac{1}{5}\) : 3,2 + 4,5 . 1\(\frac{31}{4}\) : ( -21\(\frac{1}{2}\) )
\(\frac{1}{2}x-\frac{7}{8}=\frac{5}{6}x-\frac{1}{16}\)
Tìm x:
\(\frac{7}{5}+\frac{1}{5}.x=\frac{2}{15}\)
Bài 1, Tìm x biết
a)\(\left|x\right|+\left|x+2\right|=0\)
b)\(\left|x\left(x^2-\frac{5}{4}\right)\right|=x\)
1. Thực hiện phép tính sau một cách hợp lí:
A=\(\frac{\frac{3}{7}-\frac{3}{17}+\frac{3}{37}}{\frac{5}{7}-\frac{5}{17}+\frac{5}{37}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{7}{5}-\frac{7}{4}+\frac{7}{3}-\frac{7}{2}}\)