Question

\(\frac{13-x}{x+15}=\frac{2}{3}\)

Answer 1

Ta có :

\(\frac{13-x}{x+15}=\frac{2}{3}\)

\(\Rightarrow3\left(13-x\right)=2\left(x+15\right)\)

\(\Rightarrow39-3x=2x+30\)

\(\Rightarrow5x=9\)

\(\Rightarrow x=\frac{9}{5}\)

Answer 2

\(\frac{13-x}{x+15}=\frac{2}{3}\Rightarrow3\left(13-x\right)=2\left(x+15\right)\)

\(\Rightarrow39-3x=2x+30\)

\(\Rightarrow5x=9\)

\(\Rightarrow x=\frac{9}{5}\)

Answer 3

\(\frac{13-x}{x+15}=\frac{2}{3}\)

\(\Rightarrow\left(13-x\right)3=2\left(x+15\right)\)

\(\Rightarrow39-3x=2x+30\)

\(\Rightarrow-3x-2x=30-39\)

\(\Rightarrow-5x=-9\)

\(\Rightarrow5x=9\)

\(\Rightarrow x=\frac{9}{5}\)

Vậy \(x=\frac{9}{5}\)

 

Answer 4

Ta có: \(\frac{13-x}{x+15}=\frac{2}{3}\)

=> (13-x).3=(x+15).2

=> 39-3x=2x+30

=> -3x-2x=30-39

=> -5x=-9

=> 5x=9

=> x=\(\frac{9}{5}\)

Vậy x=\(\frac{9}{5}\)