Ta có :\(\dfrac{x}{3}\) = \(\dfrac{y}{5}\) = \(\dfrac{z}{6}\) = \(\dfrac{x^2}{9}\) = \(\dfrac{2.y^2}{50}\) = \(\dfrac{z^2}{36}\)
\(\Rightarrow\) \(\dfrac{x^2-2.y^2+z^2}{9-50+36}\) = \(\dfrac{18}{-5}\)
\(\dfrac{x}{3}=\dfrac{18}{-5}\) \(\dfrac{y}{5}=\dfrac{18}{-5}\) \(\dfrac{z}{6}=\dfrac{18}{-5}\)
x.(-5)=18.3 y.(-5)=18.5 z.(-5)=18.6
x . (-5) = 54 y=18.5:(-5) z.(-5)=108
x = 54 :(-5) y=-18 z =108:(-5)
x = \(\dfrac{54}{-5}\) z=\(\dfrac{108}{-5}\)
Vậy x = \(\dfrac{54}{-5}\) ; y = -18 ; z = \(\dfrac{108}{-5}\)
