Question

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}\)va X+Y+Z =-90

Answer 1

Áp dụng t/c ......

\(\dfrac{x}{2}\)=\(\dfrac{y}{3}\)=\(\dfrac{z}{5}\)=\(\dfrac{x+y+z}{2+3+5}\)=\(\dfrac{90}{10}\)=9

\(\dfrac{x}{2}\)=9 \(\Rightarrow\)x=9.2=18

\(\dfrac{y}{3}\)=9\(\Rightarrow\)y=9.3=27

\(\dfrac{z}{5}\)=9\(\Rightarrow\)z=9.5=45

Vậy ......

Answer 2

Áp dụng tính chất cảu dãy tỉ số bằng nhau ta có:

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}=\dfrac{x+y+z}{2+3+5}=\dfrac{-90}{10}=-9\)

(do x+y+z=-90)

\(\Rightarrow x=-9.2=-18;y=-9.3=-27;z=-9.5=-45\)

Vậy \(x=-18;y=-27;z=-45\)

Chúc bạn học tốt!!!