\(\dfrac{x-5\sqrt{x}+6}{\sqrt{x}-3}=\dfrac{x-2\sqrt{x}-3\sqrt{x}+6}{\sqrt{x}-3}=\dfrac{\sqrt{x}\left(\sqrt{x}-2\right)-3\left(\sqrt{x}-2\right)}{\sqrt{x}-3}=\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}{\sqrt{x}-3}=\sqrt{x}-2\)
\(\dfrac{x-5\sqrt{x}+6}{\sqrt{x}-3}=\dfrac{x-2\sqrt{x}-3\sqrt{x}+6}{\sqrt{x}-3}=\dfrac{\sqrt{x}\left(\sqrt{x}-2\right)-3\left(\sqrt{x}-2\right)}{\sqrt{x}-3}=\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}{\sqrt{x}-3}=\sqrt{x}-2\)
tính
\(a,\sqrt{32+10\sqrt{7}}+\sqrt{32-10\sqrt{7}}\)
\(b,\sqrt{13+30\sqrt{2+\sqrt{9+4\sqrt{2}}}}\)
\(c,\dfrac{3-\sqrt{x}}{9-x}\) với \(x\ge0,x\ne9\)
\(d,\dfrac{x-5\sqrt{x}+6}{\sqrt{x}-3}\) với \(x\ge0,x\ne9\)
\(e,\dfrac{x-3\sqrt{x}+2}{\sqrt{x}-1}\) với \(x\ge0,x\ne1\)
\(f,\dfrac{x\sqrt{x}+64}{\sqrt{x}+4}\) với \(x\ge0\)
\(g,\dfrac{x\sqrt{x}-y\sqrt{y}}{\sqrt{x}-\sqrt{y}}\) với \(x\ge0,y\ge0,x\ne y\)
\(h,6-2x-\sqrt{9-6x+x^2}\) với \(x< 3\)
\(i,\sqrt{x+2+2\sqrt{x+1}}\) với \(x\ge1\)
Rút gọn bt
a) \(\dfrac{3-\sqrt{x}}{x-9}\:vớix\ge0,x\ne9\)
b) 6-2x-\(\sqrt{9-6x+x^2}vớix< 3\)
tìm x biết
a)\(\sqrt{1-12x+36x^2}=5\)
Rút gọn biểu thức:
a)\(\sqrt{\left(a-5\right)^2}\) với \(a\le5\)
b)\(x-4+\sqrt{x^2-8x+16}\)với \(x< 4\)
c)\(\dfrac{3-\sqrt{x}}{x-9}\) (với \(x\ge0;x\ne9\))
1.\(\sqrt{-4x^2+25}=x\)
2.\(\sqrt{3x^2-4x+3}=1-2x\)
3. \(\sqrt{4\left(1-x\right)^2}-\sqrt{3}=0\)
4.\(\dfrac{3\sqrt{x+5}}{\sqrt{ }x-1}< 0\)
5. \(\dfrac{3\sqrt{x-5}}{\sqrt{x+1}}\ge0\)
Giúp mình nhé!!
2. Rut gon bieu thuc:
a) \(A=\sqrt{x-2+2\sqrt{x-3}}+\sqrt{x+6+6\sqrt{x-3}},voix>=3\)
3. Tim GTNN cua bieu thuc:
a) \(A=\sqrt{4x^2-12x+9}+\sqrt{x^2-10x+25}+\sqrt{9x^2-6x+1}+\sqrt{16x^2-72x+81}\)
b) \(B=\dfrac{1}{2}\sqrt{x^2}+\sqrt{x^2-2x+1}\)
Giup minh nhe!!
1. Rut gon bieu thuc:
a) \(A=\sqrt{x-2+2\sqrt{x-3}}+\sqrt{x+6+6\sqrt{x-3}}voix>=3\)
Cho hai biểu thức A=\(\frac{\sqrt{x+1}}{\sqrt{x}-3}\), B= \(\frac{2\sqrt{x}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}\left(x\ge0,x\ne9\right)\)
a) Tính giá trị của A khi x =25
b) Rút gọn biệu thức P=B:A
c) Tìm GTNN của P
Giúp mình nhé!!
Bài 1: CMR:
a) \(\sqrt{\left(x-2\right)^2}+x+2=\left\{2\: x\left(voix>=2\right),4\left(voix< 2\right)\right\}\)
b)\(x-3+\sqrt{x^2-6x+9=}\left\{2\left(x-3\right)\left(voix>=3\right),0\left(voix< 3\right)\right\}\)
Giup minh nhe!!
1. Rut gon bieu thuc:
a) \(A=\sqrt{11-6\sqrt{2}}+3+\sqrt{2}\)
b) \(B=\sqrt{12+2\sqrt{11}}+\sqrt{12-2\sqrt{11}}\)
2. Rut gon bieu thuc:
a) \(A=\sqrt{x-2+2\sqrt{x-3}}+\sqrt{x+6+6\sqrt{x-3}},voix>=3\)
3. Tim GTNN cua bieu thuc:
a) \(A=\sqrt{4x^2-12x+9}+\sqrt{x^2-10x+25}+\sqrt{9x^2-6x+1}+\sqrt{16x^2-72x+81}\)
b) \(B=\dfrac{1}{2}\sqrt{x^2}+\sqrt{x^2-2x+1}\)