=>(x-4)^2=36
=>x-4=6 hoặc x-4=-6
=>x=-2 hoặc x=10
Đúng 0
Bình luận (0)
Đại số lớp 7
Các câu hỏi tương tự
5. \(3-1\dfrac{1}{2}-x+\dfrac{5}{4}=2-\left|1\dfrac{1}{8}-\dfrac{5}{12}\right|\) 6. \(3\dfrac{1}{14}-5\dfrac{1}{3}-\dfrac{4}{7}+\dfrac{11}{21}=x-\dfrac{1}{2}\) 7. \(\dfrac{11}{-40}+\dfrac{4}{5}-\left|\dfrac{3}{4}-1\dfrac{5}{12}\right|=\dfrac{3}{20}-x\)
5. \(3-1\dfrac{1}{2}-x+\dfrac{5}{4}=2-\left|1\dfrac{1}{8}-\dfrac{5}{12}\right|\) 6. \(3\dfrac{1}{14}-5\dfrac{1}{3}-\dfrac{4}{7}+\dfrac{11}{21}=-\dfrac{1}{2}\) 7. \(\dfrac{11}{-40}+\dfrac{4}{5}-\left|\dfrac{3}{4}-1\dfrac{5}{12}\right|=\dfrac{3}{20}-X\)
giúp mk vs :(( ( tìm x )
\(\dfrac{-4}{x}=\dfrac{x}{-49}\); \(\dfrac{3.5}{x-3}=\dfrac{5}{3}\)
(2x + 1) : 2 = 12 : 3 ; ( 2x - 14 ): 3= 12 :9
giúp mk nhaa vội lém á :((
1. Tìm x biết :
a) dfrac{x+4}{2001}+dfrac{x+3}{2002}dfrac{x+2}{2003}+dfrac{x+1}{2004}
b)dfrac{x+2016}{11}+dfrac{x+2017}{12}dfrac{x+2010}{5}dfrac{x+2015}{10}
c)dfrac{x+3}{5}+dfrac{x+4}{4}+dfrac{x+5}{3}+dfrac{x+12}{2}-1
d) (x-7)(x-6)0
e)^{x^{ }24x}
f) (x-8)(x+2) đạt giá trị âm
g) dfrac{x-2}{x-4}đạtgiatridương
Đọc tiếp
1. Tìm x biết :
a) \(\dfrac{x+4}{2001}+\dfrac{x+3}{2002}=\dfrac{x+2}{2003}+\dfrac{x+1}{2004}\)
b)\(\dfrac{x+2016}{11}+\dfrac{x+2017}{12}=\dfrac{x+2010}{5}\dfrac{x+2015}{10}\)
c)\(\dfrac{x+3}{5}+\dfrac{x+4}{4}+\dfrac{x+5}{3}+\dfrac{x+12}{2}=-1\)
d) (x-7)(x-6)=0
e)\(^{x^{ }2=4x}\)
f) (x-8)(x+2) đạt giá trị âm
g) \(\dfrac{x-2}{x-4}đạtgiatridương\)
a) \(\dfrac{3}{4}+x=\dfrac{8}{13}\)
b) \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
c)\(2x\left(x-\dfrac{1}{7}\right)=0\)
d)\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\dfrac{3}{4}+x=\dfrac{8}{13}\)
b) -x - 2 = \(\dfrac{5}{4}\) c) \(\dfrac{4}{3}-\left(x-\dfrac{1}{5}\right)=\left|\dfrac{-3}{10}+\dfrac{1}{2}\right|-\dfrac{1}{6}\) d) \(\dfrac{1}{3}-\left(\dfrac{2}{3}-x+\dfrac{5}{4}\right)=\dfrac{7}{12}-\left(\dfrac{5}{2}-\dfrac{13}{6}\right)\)
3 tháng 1 2022 lúc 9:01
Tìm x biết:
\(\dfrac{3}{5}\cdot\left(2x-\dfrac{1}{3}\right)+\dfrac{4}{15}=\dfrac{12}{30}\).
Tìm x :a)dfrac{49}{81}dfrac{7^x}{9} b)dfrac{-64}{343}(dfrac{-4^x}{7})c)dfrac{9}{144}dfrac{3^x}{12} d)dfrac{-1}{32}(dfrac{-1^x}{2})Giúp với ạ bài khó quá . Em cảm ơn ạ !
Đọc tiếp
Tìm x :
a)\(\dfrac{49}{81}\)=\(\dfrac{7^x}{9}\) b)\(\dfrac{-64}{343}\)=(\(\dfrac{-4^x}{7}\))
c)\(\dfrac{9}{144}\)=\(\dfrac{3^x}{12}\) d)\(\dfrac{-1}{32}\)=(\(\dfrac{-1^x}{2}\))
Giúp với ạ bài khó quá . Em cảm ơn ạ !
Tìm x:
\(\dfrac{2}{\left(x-1\right)\left(x-3\right)}+\dfrac{5}{\left(x-3\right)\left(x-8\right)}+\dfrac{12}{\left(x-8\right)\left(x-20\right)}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)
\(\dfrac{x+1}{1}+\dfrac{2x+3}{3}+\dfrac{3x+5}{5}+...+\dfrac{10x+19}{19}=12+\dfrac{4}{3}+\dfrac{6}{5}+...+\dfrac{20}{19}\)