\(\Leftrightarrow1+\dfrac{x-2}{x+1}=\dfrac{5}{2\left(x-1\right)}\)
\(\Leftrightarrow2\left(x^2-1\right)+2\left(x-1\right)\left(x-2\right)=5\left(x+1\right)\)
\(\Leftrightarrow2x^2-2+2x^2-6x+4-5x-5=0\)
\(\Leftrightarrow4x^2-11x-3=0\)
\(\Leftrightarrow4x^2-12x+x-3=0\)
=>(x-3)(4x+1)=0
=>x=3 hoặc x=-1/4