Question

\((\dfrac{\chi}{2}+\dfrac{3}{4})^2=\dfrac{1}{16}\)

Answer 1

Ta có: \(\left(\dfrac{1}{2}x+\dfrac{3}{4}\right)^2=\dfrac{1}{16}\)

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{-1}{4}\\\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{1}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x=-1\\\dfrac{1}{2}x=\dfrac{-1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=1\end{matrix}\right.\)

Answer 2

`(x/2 + 3/4)^2 = 1/16`

`=> (x/2 + 3/4)^2 = (1/4)^2`

Xét `x/2 + 3/4 = 1/4`

`=> x/2 = 1`

`=> x = 2`

Xét `x/2 + 3/4 = -1/4`

`=> x/2 = 1/2`

`=> x = 1`

Vậy `x = 1;2`

(Chúc bạn học tốt)

Answer 3

\(\left(\dfrac{x}{2}+\dfrac{3}{4}\right)^2=\dfrac{1}{16}\)