\(1\dfrac{3}{5}+\dfrac{\dfrac{2}{7}+\dfrac{2}{17}+\dfrac{2}{37}}{\dfrac{5}{7}+\dfrac{5}{17}+\dfrac{5}{37}}\cdot x=\dfrac{16}{5}\\ 1\dfrac{3}{5}+\dfrac{2\left(\dfrac{1}{7}+\dfrac{1}{17}+\dfrac{1}{37}\right)}{5\left(\dfrac{1}{7}+\dfrac{1}{17}+\dfrac{1}{37}\right)}\cdot x=\dfrac{16}{5}\\ \dfrac{8}{5}+\dfrac{2}{5}\cdot x=\dfrac{16}{5}\\ \dfrac{2}{5}\cdot x=\dfrac{16}{5}-\dfrac{8}{5}=\dfrac{8}{5}\\ x=\dfrac{8}{5}:\dfrac{2}{5}=\dfrac{8}{5}\cdot\dfrac{5}{2}=4\)
suy ra:8/5+2.(1/7+1/17+1/37)/5.(1/7+1/17+1/37).x=16/5
8/5+2/5.x=16/5
x=(16/5-8/5):2/5
x=8/5:2/5
x=40/10=4
Vậy x =4.
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