Question

\(\dfrac{5-\sqrt{5}}{\sqrt{5}-1}\)

Các bn giúp mik với

\(\dfrac{\sqrt{15}-\sqrt{6}}{\sqrt{5}-\sqrt{2}}\)

giúp nốt câu này 

\(\dfrac{\sqrt{10}-\sqrt{2}}{\sqrt{15}-1}+\dfrac{2-\sqrt{2}}{\sqrt{2}-1}\)

và câu này nx hihihi

Answer 1

a: \(=\dfrac{\sqrt{5}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}=\sqrt{5}\)

b: \(=\dfrac{\sqrt{3}\left(\sqrt{5}-\sqrt{2}\right)}{\sqrt{5}-\sqrt{2}}=\sqrt{3}\)

c:

Sửa đề: Căn 5

 \(=\dfrac{\sqrt{2}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}+\dfrac{\sqrt{2}\left(\sqrt{2}-1\right)}{\sqrt{2}-1}\)

\(=2\sqrt{2}\)

Answer 2

\(a,=\dfrac{\sqrt{5}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}=\sqrt{5}\\ b,=\dfrac{\sqrt{3}\left(\sqrt{5}-\sqrt{2}\right)}{\sqrt{5}-\sqrt{2}}=\sqrt{3}\\ \)

Sửa đề \(\dfrac{\sqrt{10}-\sqrt{2}}{\sqrt{5}-1}+\dfrac{2-\sqrt{2}}{\sqrt{2}-1}=\dfrac{\sqrt{2}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}+\dfrac{\sqrt{2}\left(\sqrt{2}-1\right)}{\sqrt{2}-1}=\sqrt{2}+\sqrt{2}=2\sqrt{2}\)