Question

\(\dfrac{2x+1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)

Answer 1

\(\Rightarrow4x+2-3x+6=12-8x-12x\Leftrightarrow x+8=12-20x\)

\(\Leftrightarrow21x=4\Leftrightarrow x=\dfrac{4}{21}\)

Answer 2

\(\Leftrightarrow\dfrac{2\left(2x+1\right)}{12}-\dfrac{3\left(x-2\right)}{12}=\dfrac{4\left(3-2x\right)}{12}-\dfrac{12x}{12}\)

\(\Leftrightarrow4x+2-3x+6=12-8x-12x\)

\(\Leftrightarrow21x=4\)

\(\Leftrightarrow x=\dfrac{4}{21}\)

Answer 3

\(\dfrac{2x+1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\\ \Leftrightarrow\dfrac{2\left(2x+1\right)}{12}-\dfrac{3\left(x-2\right)}{12}-\dfrac{4\left(3-2x\right)}{12}+\dfrac{12x}{12}=0\\ \Leftrightarrow4x+2-3x+6-12+8x+12x=0\\ \Leftrightarrow21x-4=0\\ \Leftrightarrow x=\dfrac{4}{21}\)