Question

\(\dfrac{1}{\sqrt{x}+2}-\dfrac{2}{\sqrt{x}-2}-\dfrac{\sqrt{x}}{4-x}\)

Answer 1

\(=\dfrac{\sqrt{x}-2-2\sqrt{x}-4+\sqrt{x}}{x-4}=\dfrac{-6}{x-4}\)

Answer 2

\(=\dfrac{\sqrt{x}-2}{x-4}-\dfrac{2\left(\sqrt{x}+2\right)}{x-4}+\dfrac{\sqrt{x}}{x-4}\\ =\dfrac{\sqrt{x}-2-2\sqrt{x}-4+\sqrt{x}}{x-4}\\ =\dfrac{-6}{x-4}\)