Question

\(\dfrac{1}{\sqrt{4x-8}}=2\)

Answer 1

\(\dfrac{1}{\sqrt{4x-8}}=2\) ( ĐKXĐ: \(x\ge0;x\ne2\))

<=> \(2\sqrt{4x-8}=1\)

<=> \(2.2\sqrt{x-2}=1\)

<=>\(\sqrt{x-2}=\dfrac{1}{4}\)

<=>\(x-2=\dfrac{1}{16}\)

<=> \(x=\dfrac{33}{16}\) ( Thỏa mãn ĐKXĐ)

Answer 2

Ta có: \(\dfrac{1}{\sqrt{4x-8}}=2\)

\(\Leftrightarrow\dfrac{1}{2\sqrt{x-2}}=2\)

\(\Leftrightarrow\dfrac{1}{\sqrt{x-2}}=1\)

\(\Leftrightarrow\sqrt{x-2}=1\)

\(\Leftrightarrow x-2=1\)

\(\Leftrightarrow x=3\)

Vậy: \(x=3\)

_Good luck to you_