\(\Leftrightarrow\dfrac{1}{2}x+\dfrac{1}{2}+\dfrac{1}{4}x+\dfrac{3}{4}=3-\dfrac{1}{3}x-\dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{1}{2}x+\dfrac{1}{4}x+\dfrac{1}{3}x=-\dfrac{2}{3}-\dfrac{1}{2}-\dfrac{3}{4}+3\)
\(\Leftrightarrow\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{3}\right)x=\dfrac{13}{12}\)
\(\Leftrightarrow\dfrac{13}{12}x=\dfrac{13}{12}\)
\(\Leftrightarrow x=1\)