Mg + 2 HCl ---> MgCl2 + H2;
0,1------0,2---------------0,1---------0,1 (mol)
a. nMg=2,4/24=0,1 (mol)
=> nH2=0,1(mol)=> VH2=0,1*22,4=2,24 (l)
b. nHCl=0,1*2=0,2(mol)=> mHCl=0,2*36,5=7,3 (g)
C%dd HCl=\(\dfrac{7,3\cdot100}{50}=14,6\%\)
c. nMgCl2=0,1(mol)=> mMgCl2=0,1*95=9,5(g).