cho hỏi 10gam hỗn hợp là Mg với Cu hay Mg với CuO zậy
\(n_{H_2}=0,2mol\)
Mg+2HCl\(\rightarrow\)MgCl2+H2
CuO+2HCl\(\rightarrow\)CuCl2+H2O
\(n_{Mg}=n_{H_2}=0,2mol\)
mMg=0,2.24=4,8g
mCuO=10-4,8=5,2g\(\rightarrow\)nCuO=5,2:80=0,065mol
\(\%Mg=\dfrac{4,8.100}{10}=48\%\)
%CuO=52%
\(n_{HCl}=2\left(0,2+0,065\right)=0,53mol\)
\(C\%_{HCl}\dfrac{0,53.36,5.100}{200}=9,6725\%\)
mdd=10+200-0,2.2=209,6g
\(C\%_{MgCl_2}=\dfrac{0,2.95.100}{209,6}\approx9,1\%\)
\(C\%_{CuCl_2}=\dfrac{0,065.135.100}{209,6}\approx4,2\%\)