Ta có
NaOH + HCl \(\rightarrow\) NaCl + H2O
x...............x...........x..........x
KOH + HCl \(\rightarrow\) KCl + H2O
y..........y.............y.............y
=> \(\left\{{}\begin{matrix}40x+56y=4\\58,5x+74,5y=5,48\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=0,03\\y=0,05\end{matrix}\right.\)
=> mNaOH = 40 . 0,03 = 1,2 ( gam )
=> mKOH = 4 - 1,2 = 2,8 ( gam )
=> VHCl = n : CM = ( 0,05 + 0,03 ) : 2 = 0,04 ( lít )