\(lim_{x->1}\frac{\sqrt{6-2x}-\sqrt{x^2+3}}{\left(x-1\right)^2}\)

Chứng minh rằng phương trình \(x^3-2mx^2+x-1=0\) có nghiệm với mọi m

\(lim_{x->\pm\infty}\sqrt{x^2-3x+4}\)

\(lim_{x->\pm\infty}x\left(\sqrt{x^2+5}+x\right)\)

\(lim_{x->2019}\frac{\sqrt{x+285}-48}{\sqrt{x-2018}-\sqrt{2020-x}}\)

\(lim_{x->1}\frac{\sqrt[3]{6x-5}-\sqrt{4x-3}}{\left(x-1\right)^2}\)

l\(lim_{x->0}\left(1-x\right)tan\frac{\pi x}{2}\)

\(lim_{x->0}\frac{x.sin2x}{1-cos2x}\)

\(lim_{x->0}\frac{\sqrt{1-x}-1}{x}\)

\(lim_{x->0-}\frac{1}{x}\left(\frac{1}{x+1}-1\right)\)

\(lim_{x->0-}\frac{2x+\sqrt{-x}}{5x-\sqrt{-x}}\)

\(lim\frac{1}{n^3}.sin\frac{n^2\pi}{3}\)

I=\(lim_{x->1}\frac{\sqrt{x^3-x^2}}{\sqrt{x-1}+1-x}\) Chứng minh I không tồn tại

\(lim_{x->1}\frac{\sqrt[3]{8x+11}-\sqrt{x+7}}{x^2-3x+2}\)