a) ĐKXĐ: \(x\notin\left\{0;-1\right\}\)
Ta có: \(\dfrac{1}{x}-\dfrac{2}{x+1}=\dfrac{3}{x^2+x}\)
\(\Leftrightarrow\dfrac{x+1}{x\left(x+1\right)}-\dfrac{2x}{x\left(x+1\right)}=\dfrac{3}{x\left(x+1\right)}\)
Suy ra: \(-x+1=3\)
\(\Leftrightarrow-x=2\)
hay x=-2(thỏa ĐK)
Vậy: S={-2}
giải phương trình:
a) \(\left(\dfrac{x}{2}+1\right)^3-\dfrac{x^3}{2}-4=0\)
b) \(\dfrac{3-x}{2007}+1=\dfrac{2-x}{2008}-\dfrac{x}{2009}\)
1, \(\dfrac{\left(2x-3\right)\cdot\left(2x+3\right)}{8}=\dfrac{\left(x-4\right)^2}{6}+\dfrac{\left(x-2\right)^2}{3}\)
2, \(x+2-\dfrac{2x-\dfrac{2x-5}{6}}{15}=\dfrac{7x-\dfrac{x-3}{2}}{5}\)
3, \(1-\dfrac{x-\dfrac{1+x}{3}}{3}=\dfrac{x}{2}-\dfrac{2x-\dfrac{10-7}{3}}{2}\)
4, \(\dfrac{x+1}{99}+\dfrac{x+3}{97}+\dfrac{x+5}{95}=\dfrac{x+7}{93}+\dfrac{9+x}{91}+\dfrac{x+11}{89}\)
Các bạn làm giúp mình bài này . Mình gấp lắm !
Giải phương trình :
\(\dfrac{1}{x\left(x-1\right)}+\dfrac{1}{\left(x-1\right)\left(x-2\right)}+\dfrac{1}{\left(x-2\right)\left(x-3\right)}+\dfrac{1}{\left(x-3\right)\left(x-4\right)}=\dfrac{1}{x-4}+2\)
bài 1 : Giải cac phuong trinh sau
a, \(\dfrac{x-3}{5}=6-\dfrac{1-2x}{3}\)
b, \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
c, \(2\left(x+\dfrac{3}{5}\right)=5-\left(\dfrac{13}{5}+x\right)\)
d, \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
e, \(\dfrac{x-1}{2}+\dfrac{x-1}{4}=1-\dfrac{2\left(x-1\right)}{3}\)
g, \(\dfrac{2-x}{2001}-1=\dfrac{1-x}{2002}-\dfrac{x}{2003}\)
Các bạn ơi ! giúp mik với !!! chiều nay học roi
Giải phương trình:
\(8\left(x+\dfrac{1}{x}\right)^2+4\left(x^2+\dfrac{1}{x^2}\right)^2-4\left(x^2+\dfrac{1}{x^2}\right)\left(x+\dfrac{1}{x}\right)^2=\left(x+4\right)^2\)
Giải phương trình: \(\left(\dfrac{x+1}{x+2}\right)^2+\dfrac{x+1}{x-4}-3.\left(\dfrac{2x-4}{x-4}\right)^2=0\)
Giải phương trình:
a) 4x-16=3x(x-4)
b) \(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x\left(x-2\right)}\)
giải phương trình
a, \(\left(x^2+x+1\right).\left(x^2+x+2\right)=12\)
b,\(\dfrac{x+1}{2014}+\dfrac{x+2}{2013}=\dfrac{x+3}{2012}+\dfrac{x+4}{2011}\)
giải phương trình:
a,\(x^2-x+y^2+y=-\dfrac{1}{2}\)
b,\(\dfrac{x^2}{3}+\dfrac{48}{x^2}-10\left(\dfrac{x}{3}-\dfrac{4}{x}\right)=0\)
