`a,-10/25=(-2 xx 5)/(5 xx 5)=-2/5`
`b,(-9)/(-27)=(-9 xx 1)/(-9 xx 3)=1/3`
a) \(\dfrac{-10}{25}=\dfrac{-10:5}{25:5}=\dfrac{-2}{5}\)
b) \(\dfrac{-9}{-27}=\dfrac{-9:\left(-9\right)}{-27:\left(-9\right)}=\dfrac{1}{3}\)
a)\(\dfrac{\text{-10}}{\text{25}}\) =\(\dfrac{\text{-10:5}}{\text{25:5}}\)=\(\dfrac{-2}{5}\)
b) \(\dfrac{\text{-9}}{\text{-27}}\)=\(\dfrac{-9:\left(-9\right)}{\text{-27}:\left(-9\right)}\)=\(\dfrac{1}{3}\)
a,−1025=−2×55×5=−25a,-1025=-2×55×5=-25
b,−9−27=−9×1−9×3=13
a) \(\dfrac{-10}{25}=\dfrac{-10:5}{25:5}=\dfrac{-2}{5}\)
b) \(\dfrac{-9}{-27}=\dfrac{-9:\left(-3\right)}{-27:\left(-3\right)}=\dfrac{1}{3}\)