Đặt \(A=1+2+2^2+...+2^{99}+2^{100}\)
\(\Rightarrow2A=2.\left(1+2+2^2+...+2^{99}+2^{100}\right)\)
\(=2+2^2+2^3+...+2^{100}+2^{101}\)
Có \(2A-A=\left(2+2^2+2^3+...+2^{100}+2^{101}\right)-\left(1+2^{ }+2^2+...+2^{99}+2^{100}\right)\)
\(A=2+2^2+2^3+...+2^{100}+2^{101}-1-2-2^2-...-2^{99}-2^{100}\)
\(A=2^{101}-1\) (đpcm)