Đặt \(A=\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^9}\)
\(\Rightarrow2A=1+\frac{1}{2}+...+\frac{1}{2^8}\)
\(\Rightarrow2A-A=1-\frac{1}{2^9}\)
\(\Rightarrow A=1-\frac{1}{2^9}\)
\(\Rightarrow\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^9}=1-\frac{1}{2^9}\left(đpcm\right)\)