\(x^2+4x+5\)
\(=x^2+2x+2x+5\)
\(=\left(x^2+2x\right)+\left(2x+4\right)+1\)
\(=x\left(x+2\right)+2\left(x+2\right)+1\)
\(=\left(x+2\right)\left(x+2\right)+1\)
\(=\left(x+2\right)^2+1\)
Với mọi x ta có :
\(\left(x+2\right)^2\ge0\)
\(1>0\)
\(\Leftrightarrow\left(x+2\right)^2+1>0\)
\(\Leftrightarrow x^2+4x+5>0\)
\(\Leftrightarrow x^2+4x+5\) vô nghiệm