Ta có :
\(4x^2+4x+6=4x^2+2x+2x+1+5\\ =2x\left(2x+1\right)+\left(2x+1\right)+5\\ =\left(2x+1\right)\left(2x+1\right)+5\\ =\left(2x+1\right)^2+5\)
Vì : \(\left(2x+1\right)^2\ge0\forall x\Rightarrow\left(2x+1\right)^2+5\ge5\forall x\\ \RightarrowĐathứcvônghiệm\\ \RightarrowĐpcm\)