Sửa đề: \(T=\frac{x}{1+4y^2}+\frac{y}{1+4z^2}+\frac{z}{1+4x^2}\)
\(T=x-\frac{4xy^2}{1+4y^2}+y-\frac{4yz^2}{1+4z^2}+z-\frac{4zx^2}{1+4x^2}\)
\(T\ge x+y+z-\frac{4xy^2}{4y}-\frac{4yz^2}{4z}-\frac{4zx^2}{4x}\)
\(T\ge\frac{3}{2}-\left(xy+yz+zx\right)\ge\frac{3}{2}-\frac{1}{3}\left(x+y+z\right)^2=\frac{3}{4}\)
Dấu "=" xảy ra khi \(x=y=z=\frac{1}{2}\)