\(VT=\left(x+\dfrac{1}{x}\right)^2+\left(y+\dfrac{1}{y}\right)^2\ge\dfrac{1}{2}\left(x+\dfrac{1}{x}+y+\dfrac{1}{y}\right)^2\)
\(VT\ge\dfrac{1}{2}\left(x+y+\dfrac{1}{x}+\dfrac{1}{y}\right)^2\ge\dfrac{1}{2}\left(x+y+\dfrac{4}{x+y}\right)^2=\dfrac{25}{2}\)
Dấu "=" xảy ra khi \(x=y=\dfrac{1}{2}\)
cho x,y,z là số thực dương thỏa mãn xy+yz+xz=xyz
cmr \(\dfrac{xy}{z^3\left(1+x\right)\left(1+y\right)}+\dfrac{yz}{x^3\left(1+y\right)\left(1+z\right)}+\dfrac{xz}{y^3\left(1+x\right)\left(1+z\right)}\ge\dfrac{1}{16}\)
Cho các số thực dương x,y,z thỏa mãn xyz ≤ 1
CMR:\(\dfrac{x\left(1-y^3\right)}{y^3}+\dfrac{y\left(1-z^3\right)}{z^3}+\dfrac{z\left(1-x^3\right)}{x^3}\)≥ 0
Cho x,y,z > 0 có xy+yz+xz = 3xyz CMR : \(\dfrac{x^3}{x^2+z}+\dfrac{y^3}{y^2+x}+\dfrac{z^3}{z^2+y}\ge\dfrac{1}{2}\left(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}\right)\)
chứng minh rằng :
a, x+2y+\(\dfrac{25}{x}\)+\(\dfrac{27}{y^2}\)\(\ge\) 19 ( \(\forall\)x,y \(\)> 0 )
b, \(x+\dfrac{1}{\left(x-y\right)y}\ge3\) ( \(\forall\)x>y>0 )
c,\(\dfrac{x}{2}+\dfrac{16}{x-2}\ge13\left(\forall x>2\right)\)
d, \(a+\dfrac{1}{a^2}\ge\dfrac{9}{4}\left(\forall x\ge2\right)\)
e, a+\(\dfrac{1}{a\left(a-b\right)^2}\ge2\sqrt{2}\) ( \(\forall x>y\ge0\))
f, \(\dfrac{2a^3+1}{4b\left(a-b\right)}\ge3[\forall a\ge\dfrac{1}{2};\dfrac{a}{b}>1]\)
g, x+\(\dfrac{4}{\left(x-y\right)\left(y+1\right)^2}\ge3\left(\forall x>y\ge0\right)\)
h, \(2a^4+\dfrac{1}{1+a^2}\ge3a^2-1\)
Cho x ; y là các số thực dương thỏa mãn
\(\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{2}\)
Chứng minh rằng :
\(\sqrt{x}+\sqrt{y}\ge4\)
Bài 1:Cho x, y, z >0 thỏa mãn x+y+z=12.Tìm GTLN của biểu thức
\(M=\dfrac{2x+y+z-15}{x}+\dfrac{x+2y+z-15}{y}+\dfrac{x+y+2z-15}{z}\)
Bài 2:Cho a,b,c là số thực dương. Tìm GTNN của biểu thức
\(P=\dfrac{\left(a+b+c\right)^2}{30\left(a^2+b^2+c^2\right)}+\dfrac{a^3+b^3+c^3}{4abc}-\dfrac{131\left(a^2+b^2+c^2\right)}{60\left(ab+bc+ca\right)}\)
Cho x,y,z có tích bằng 1 CMR :
\(\dfrac{1}{\left(1+x\right)^2}+\dfrac{1}{\left(1+y\right)^2}+\dfrac{1}{\left(1+z\right)^2}+\dfrac{1}{1+x+y+z}\ge1\)
Cho các số thực x,y thỏa mãn: \(\dfrac{x^2+y^2}{2}=y-2x\). Chứng minh rằng:
\(\left|\sqrt{2-2x}-\sqrt{4x+6y+20}\right|=3\sqrt{2}\)
Cho \(x,y,z,t>0\) thỏa mãn \(xyzt=1\)
Chứng minh \(\dfrac{1}{x^3\left(yz+zt+ty\right)}+\dfrac{1}{y^3\left(xz+zt+tx\right)}+\dfrac{1}{z^3\left(xy+yt+tx\right)}+\dfrac{1}{t^3\left(xy+yz+zx\right)}\ge\dfrac{1}{3}\left(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}+\dfrac{1}{t}\right)\)
