Đặt \(A=x+\frac{1}{x}\)
\(A=x+\frac{4}{x}-\frac{3}{x}\)
\(Có:x+\frac{4}{x}\ge4\Leftrightarrow\left(x-2\right)^2\ge0\)
\(x\ge2\Leftrightarrow\frac{-3}{x}\ge\frac{-3}{2}\)
\(\Rightarrow A\ge4+\frac{-3}{2}=\frac{5}{2}\)
Dấu " = " xảy ra \(\Leftrightarrow x=2\)
(Chắc là vậy)