Ta có: \(x+\dfrac{1}{x}=3\)
\(\Leftrightarrow\left(x+\dfrac{1}{x}\right)^3=3^3\)
\(\Leftrightarrow x^3+3.x^2.\dfrac{1}{x}+3.x.\left(\dfrac{1}{x}\right)^2+\left(\dfrac{1}{x}\right)^3=27\)
\(\Leftrightarrow x^3+\dfrac{1}{x^3}+3\left(x+\dfrac{1}{x}\right)=0\)
\(\Leftrightarrow x^3+\dfrac{1}{x^3}+3.3=27\)
\(\Leftrightarrow x^3+\dfrac{1}{x^3}=27-9=18\)