Question

Cho tui hỏi vs :

tìm x: a) 4 . ( \(\dfrac{1}{3}\) - x ) + \(\dfrac{1}{2}\) = \(\dfrac{5}{6}\) . x

b) \(\dfrac{5}{2}\) - 3 . ( \(\dfrac{1}{3}\) - x ) = \(\dfrac{1}{4}\) - 7.x

Answer 1

Bài 1: a) 4 . ( \(\dfrac{1}{3}\) - x ) + \(\dfrac{1}{2}\) = \(\dfrac{5}{6}\) . x

=> \(\dfrac{4}{3}\) - 4.x + \(\dfrac{1}{2}\) = \(\dfrac{5}{6}\) . x

=> \(\dfrac{11}{6}\) = \(\dfrac{29}{6}\) . x

=> x = \(\dfrac{11}{29}\) .

b) \(\dfrac{5}{2}\) - 3 . ( \(\dfrac{1}{3}\) - x ) = \(\dfrac{1}{4}\) - 7.x

=> \(\dfrac{1}{4}\) - \(\dfrac{3}{2}\) = 7.x + 3.x

=> \(\dfrac{-5}{4}\) = 10.x

=> x = \(\dfrac{-1}{8}\).