Question

cho tỉ lệ thức

\(\dfrac{3x-y}{x+y}=\dfrac{3}{4}\) tìm giá trị của tỉ số \(\dfrac{x}{y}\)

Answer 1

Ta có:

\(\dfrac{3x-y}{x+y}=\dfrac{3}{4}\\ \Rightarrow12x-4y=3x+3y\\ \Rightarrow9x=7y\\ \Rightarrow\dfrac{x}{y}=\dfrac{7}{9}\)

Vậy.........

Answer 2

\(\dfrac{3x-y}{x+y}=\dfrac{3}{4}\Rightarrow\left(3x-y\right).4=3\left(x+y\right)\)

\(\Rightarrow12x-4y=3x+3y\)

\(\Rightarrow9x=7y\)

\(\Rightarrow\)\(\dfrac{x}{y}=\dfrac{7}{9}\)