a: \(\Leftrightarrow\left(2m+2\right)^2-4m^2>=0\)
=>8m+4>=0
hay m>=-1/2
b: \(\Leftrightarrow\left(x_1+x_2\right)^2-7x_1x_2=13\)
\(\Leftrightarrow\left(-2m-2\right)^2-7m^2=13\)
\(\Leftrightarrow4m^2+8m+4-7m^2-13=0\)
\(\Leftrightarrow-3m^2+8m-9=0\)
\(\text{Δ}=8^2-4\cdot\left(-3\right)\cdot\left(-9\right)=64-4\cdot27< 0\)
Vậy: Phương trình vô nghiệm