Question

cho hỏi tìm x và y

(x+3)(y+2)=1

Answer 1

\(\left(x+3\right)\left(y+2\right)=1\)

\(\Leftrightarrow x+3;y+2\inƯ\left(1\right)\)

\(\Leftrightarrow\) Ta có các trường hợp :

\(\left\{{}\begin{matrix}x+3=1\\y+2=1\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=-1\end{matrix}\right.\)

\(\left\{{}\begin{matrix}x+3=-1\\y+2=-1\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=-4\\y=-3\end{matrix}\right.\)

Vậy...