\(y+30\%y=-1,3\\ y\left(1-30\%\right)=-1,3\\ y\cdot0,7=-1,3\\ y=-1,3:0,7\\ y=\frac{-13}{7}\)
Vậy \(y=\frac{-13}{7}\)
\(y-0,25\%y=\frac{1}{2}\\ y\left(1-0,25\%\right)=0,5\\ y\cdot0,9975=0,5\\ y=0,5:0,9975\\ y=\frac{200}{399}\)
Vậy \(y=\frac{200}{399}\)
\(0,5x+\frac{2}{3}x=\frac{7}{12}\\ x\left(\frac{1}{2}+\frac{2}{3}\right)=\frac{7}{12}\\ x\cdot\frac{7}{6}=\frac{7}{12}\\ x=\frac{7}{12}:\frac{7}{6}\\ x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
\(\frac{\frac{3x}{7+1}}{-4}=\frac{-1}{8}\\ \Rightarrow8\cdot\frac{3x}{7+1}=4\\ \Rightarrow\frac{3x}{8}=\frac{1}{2}\\ \Rightarrow2\cdot3x=8\\ \Rightarrow6x=8\\ \Rightarrow x=\frac{4}{3}\)
Vậy \(x=\frac{4}{3}\)
y+30%y=−1,3y(1−30%)=−1,3y⋅0,7=−1,3y=−1,3:0,7y=−137y+30%y=−1,3y(1−30%)=−1,3y⋅0,7=−1,3y=−1,3:0,7y=−137
Vậy y=−137y=−137
y−0,25%y=12y(1−0,25%)=0,5y⋅0,9975=0,5y=0,5:0,9975y=200399y−0,25%y=12y(1−0,25%)=0,5y⋅0,9975=0,5y=0,5:0,9975y=200399
Vậy y=200399y=200399
0,5x+23x=712x(12+23)=712x⋅76=712x=712:76x=120,5x+23x=712x(12+23)=712x⋅76=712x=712:76x=12
Vậy x=12x=12
3x7+1−4=−18⇒8⋅3x7+1=4⇒3x8=12⇒2⋅3x=8⇒6x=8⇒x=433x7+1−4=−18⇒8⋅3x7+1=4⇒3x8=12⇒2⋅3x=8⇒6x=8⇒x=43
Vậy x=43